Optimal. Leaf size=252 \[ \frac{515 d^6 \sqrt{d^2-e^2 x^2}}{21 e^6}-\frac{49 d^5 x \sqrt{d^2-e^2 x^2}}{4 e^5}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}+\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{65 d^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{4 e^6} \]
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Rubi [A] time = 0.662574, antiderivative size = 252, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 6, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {852, 1635, 1815, 641, 217, 203} \[ \frac{515 d^6 \sqrt{d^2-e^2 x^2}}{21 e^6}-\frac{49 d^5 x \sqrt{d^2-e^2 x^2}}{4 e^5}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}+\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{65 d^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{4 e^6} \]
Antiderivative was successfully verified.
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Rule 852
Rule 1635
Rule 1815
Rule 641
Rule 217
Rule 203
Rubi steps
\begin{align*} \int \frac{x^5 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^4} \, dx &=\int \frac{x^5 (d-e x)^4}{\left (d^2-e^2 x^2\right )^{3/2}} \, dx\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}-\frac{\int \frac{(d-e x)^3 \left (-\frac{4 d^5}{e^5}+\frac{d^4 x}{e^4}-\frac{d^3 x^2}{e^3}+\frac{d^2 x^3}{e^2}-\frac{d x^4}{e}\right )}{\sqrt{d^2-e^2 x^2}} \, dx}{d}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{\int \frac{\frac{28 d^8}{e^3}-\frac{91 d^7 x}{e^2}+\frac{112 d^6 x^2}{e}-77 d^5 x^3+56 d^4 e x^4-55 d^3 e^2 x^5+28 d^2 e^3 x^6}{\sqrt{d^2-e^2 x^2}} \, dx}{7 d e^2}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}-\frac{\int \frac{-\frac{168 d^8}{e}+546 d^7 x-672 d^6 e x^2+462 d^5 e^2 x^3-476 d^4 e^3 x^4+330 d^3 e^4 x^5}{\sqrt{d^2-e^2 x^2}} \, dx}{42 d e^4}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{\int \frac{840 d^8 e-2730 d^7 e^2 x+3360 d^6 e^3 x^2-3630 d^5 e^4 x^3+2380 d^4 e^5 x^4}{\sqrt{d^2-e^2 x^2}} \, dx}{210 d e^6}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}-\frac{\int \frac{-3360 d^8 e^3+10920 d^7 e^4 x-20580 d^6 e^5 x^2+14520 d^5 e^6 x^3}{\sqrt{d^2-e^2 x^2}} \, dx}{840 d e^8}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{\int \frac{10080 d^8 e^5-61800 d^7 e^6 x+61740 d^6 e^7 x^2}{\sqrt{d^2-e^2 x^2}} \, dx}{2520 d e^{10}}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}-\frac{49 d^5 x \sqrt{d^2-e^2 x^2}}{4 e^5}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}-\frac{\int \frac{-81900 d^8 e^7+123600 d^7 e^8 x}{\sqrt{d^2-e^2 x^2}} \, dx}{5040 d e^{12}}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}+\frac{515 d^6 \sqrt{d^2-e^2 x^2}}{21 e^6}-\frac{49 d^5 x \sqrt{d^2-e^2 x^2}}{4 e^5}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{\left (65 d^7\right ) \int \frac{1}{\sqrt{d^2-e^2 x^2}} \, dx}{4 e^5}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}+\frac{515 d^6 \sqrt{d^2-e^2 x^2}}{21 e^6}-\frac{49 d^5 x \sqrt{d^2-e^2 x^2}}{4 e^5}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{\left (65 d^7\right ) \operatorname{Subst}\left (\int \frac{1}{1+e^2 x^2} \, dx,x,\frac{x}{\sqrt{d^2-e^2 x^2}}\right )}{4 e^5}\\ &=\frac{d^4 (d-e x)^4}{e^6 \sqrt{d^2-e^2 x^2}}+\frac{515 d^6 \sqrt{d^2-e^2 x^2}}{21 e^6}-\frac{49 d^5 x \sqrt{d^2-e^2 x^2}}{4 e^5}+\frac{121 d^4 x^2 \sqrt{d^2-e^2 x^2}}{21 e^4}-\frac{17 d^3 x^3 \sqrt{d^2-e^2 x^2}}{6 e^3}+\frac{11 d^2 x^4 \sqrt{d^2-e^2 x^2}}{7 e^2}-\frac{2 d x^5 \sqrt{d^2-e^2 x^2}}{3 e}+\frac{1}{7} x^6 \sqrt{d^2-e^2 x^2}+\frac{65 d^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{4 e^6}\\ \end{align*}
Mathematica [A] time = 0.263833, size = 131, normalized size = 0.52 \[ \frac{\frac{\sqrt{d^2-e^2 x^2} \left (-293 d^5 e^2 x^2+162 d^4 e^3 x^3-106 d^3 e^4 x^4+76 d^2 e^5 x^5+779 d^6 e x+2144 d^7-44 d e^6 x^6+12 e^7 x^7\right )}{d+e x}+1365 d^7 \tan ^{-1}\left (\frac{e x}{\sqrt{d^2-e^2 x^2}}\right )}{84 e^6} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.073, size = 416, normalized size = 1.7 \begin{align*} -{\frac{1}{7\,{e}^{6}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{28\,{d}^{2}}{3\,{e}^{6}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{5}{2}}}}+{\frac{35\,{d}^{3}x}{3\,{e}^{5}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{3}{2}}}}+{\frac{35\,{d}^{5}x}{2\,{e}^{5}}\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}+{\frac{35\,{d}^{7}}{2\,{e}^{5}}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{- \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) }}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-{\frac{2\,dx}{3\,{e}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}-{\frac{5\,{d}^{3}x}{6\,{e}^{5}} \left ( -{x}^{2}{e}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}-{\frac{5\,{d}^{5}x}{4\,{e}^{5}}\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}-{\frac{5\,{d}^{7}}{4\,{e}^{5}}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{x}^{2}{e}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}+{\frac{{d}^{4}}{{e}^{10}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{7}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-4}}+8\,{\frac{{d}^{3}}{{e}^{9}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{7/2} \left ({\frac{d}{e}}+x \right ) ^{-3}}+{\frac{22\,{d}^{2}}{3\,{e}^{8}} \left ( - \left ({\frac{d}{e}}+x \right ) ^{2}{e}^{2}+2\,de \left ({\frac{d}{e}}+x \right ) \right ) ^{{\frac{7}{2}}} \left ({\frac{d}{e}}+x \right ) ^{-2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.66641, size = 351, normalized size = 1.39 \begin{align*} \frac{2144 \, d^{7} e x + 2144 \, d^{8} - 2730 \,{\left (d^{7} e x + d^{8}\right )} \arctan \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{e x}\right ) +{\left (12 \, e^{7} x^{7} - 44 \, d e^{6} x^{6} + 76 \, d^{2} e^{5} x^{5} - 106 \, d^{3} e^{4} x^{4} + 162 \, d^{4} e^{3} x^{3} - 293 \, d^{5} e^{2} x^{2} + 779 \, d^{6} e x + 2144 \, d^{7}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{84 \,{\left (e^{7} x + d e^{6}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{5} \left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac{5}{2}}}{\left (d + e x\right )^{4}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: NotImplementedError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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